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Module:Keppel date/doc: Difference between revisions

From Amaranth Legacy, available at amaranth-legacy.community
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Tags: Reverted 2017 source edit
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Tags: Manual revert 2017 source edit
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y_\oplus &= \text{Earth year} \\
y_\oplus &= \text{Earth year} \\
d_\oplus &= \text{Earth day of year (fractional)} \\
d_\oplus &= \text{Earth day of year (fractional)} \\
\text{days}_\oplus(y_\oplus) &= \begin{cases}
d_{\oplus_\text{max}}(y_\oplus) &= \begin{cases}
366 & (y_\oplus = 0 \pmod{4} \text{ and } y_\oplus \neq 0 \pmod{100}) \text{ or } y_\oplus = 0 \pmod{400} \\
366 & y_\oplus = 0 \pmod{4} \text{ and } y_\oplus \neq 0 \pmod{100} \text{ and } y_\oplus \neq 0 \pmod{400} \\
366 & y_\oplus = 0 \pmod{400} \\
365 & \text{otherwise}
365 & \text{otherwise}
\end{cases} \\
\end{cases} \\
\text{offset}(y_\oplus) &= \text{days}_\oplus(y_\oplus) - 287 \\
d_{\text{K}_\text{offset}}(y_\oplus) &= d_{\oplus_\text{max}}(y_\oplus) - 287 \\
\text{days}_\text{K}(y_\text{K}) &= \begin{cases}
d_{\text{K}_\text{max}}(y_\text{K}) &= \begin{cases}
391 & y_\text{K} = 65 \pmod{239} \text{ and } y_\text{K} = 2 \pmod{4} \\
391 & y_\text{K} = 65 \pmod{239} \text{ and } y_\text{K} = 2 \pmod{4} \\
390 & y_\text{K} = 65 \pmod{239} \text{ or } y_\text{K} = 2 \pmod{4} \\
390 & y_\text{K} = 65 \pmod{239} \\
390 & y_\text{K} = 2 \pmod{4} \\
389 & \text{otherwise}
389 & \text{otherwise}
\end{cases} \\
\end{cases} \\
y_\text{K} &= \begin{cases}
y_\text{K} &= \begin{cases}
y_\oplus - 892 & d_\oplus - \text{offset}(y_\oplus) \geq \frac{\text{days}_\oplus(y_\oplus)}{\text{days}_\text{K}(y_\oplus - 892)} \\
y_\oplus - 892 & d_\oplus - d_{\text{K}_\text{offset}}(y_\oplus) \geq \frac{d_{\oplus_\text{max}}(y_\oplus)}{d_{\text{K}_\text{max}}(y_\oplus - 892)} \\
y_\oplus - 892 - 1 & d_\oplus - \text{offset}(y_\oplus) < \frac{\text{days}_\oplus(y_\oplus)}{\text{days}_\text{K}(y_\oplus - 892)}
y_\oplus - 892 - 1 & d_\oplus - d_{\text{K}_\text{offset}}(y_\oplus) < \frac{d_{\oplus_\text{max}}(y_\oplus)}{d_{\text{K}_\text{max}}(y_\oplus - 892)}
\end{cases} \\
\end{cases} \\
d_\text{K} &= (\frac{d_\oplus - \text{offset}(y_\oplus)}{\text{days}_\oplus(y_\oplus)} \times \text{days}_\text{K}(y_\text{K}) - 1) \bmod{\text{days}_\text{K}(y_\text{K})} + 1 \\
d_\text{K} &= (\frac{d_\oplus - d_{\text{K}_\text{offset}}(y_\oplus)}{d_{\oplus_\text{max}}(y_\oplus)} \times d_{\text{K}_\text{max}}(y_\text{K}) - 1) \bmod{d_{\text{K}_\text{max}}(y_\text{K})} + 1 \\
L_\text{K} &= \lfloor \frac{d_\text{K} - 1}{32} \rfloor + 1 \\
L &= \lfloor \frac{d_\text{K} - 1}{32} \rfloor + 1 \\
d_{\text{K}_L} &= \lfloor (d_\text{K} - 1) \bmod{32} \rfloor + 1
d_{\text{K}_L} &= \lfloor (d_\text{K} - 1) \bmod{32} \rfloor + 1
\end{aligned}
\end{aligned}

Revision as of 21:43, March 20, 2026

Converts the current (or provided) date to a Keppel date. Used by Template:Keppel date.

Formula

\begin{aligned} y_\oplus &= \text{Earth year} \\ d_\oplus &= \text{Earth day of year (fractional)} \\ d_{\oplus_\text{max}}(y_\oplus) &= \begin{cases} 366 & y_\oplus = 0 \pmod{4} \text{ and } y_\oplus \neq 0 \pmod{100} \text{ and } y_\oplus \neq 0 \pmod{400} \\ 366 & y_\oplus = 0 \pmod{400} \\ 365 & \text{otherwise} \end{cases} \\ d_{\text{K}_\text{offset}}(y_\oplus) &= d_{\oplus_\text{max}}(y_\oplus) - 287 \\ d_{\text{K}_\text{max}}(y_\text{K}) &= \begin{cases} 391 & y_\text{K} = 65 \pmod{239} \text{ and } y_\text{K} = 2 \pmod{4} \\ 390 & y_\text{K} = 65 \pmod{239} \\ 390 & y_\text{K} = 2 \pmod{4} \\ 389 & \text{otherwise} \end{cases} \\ y_\text{K} &= \begin{cases} y_\oplus - 892 & d_\oplus - d_{\text{K}_\text{offset}}(y_\oplus) \geq \frac{d_{\oplus_\text{max}}(y_\oplus)}{d_{\text{K}_\text{max}}(y_\oplus - 892)} \\ y_\oplus - 892 - 1 & d_\oplus - d_{\text{K}_\text{offset}}(y_\oplus) < \frac{d_{\oplus_\text{max}}(y_\oplus)}{d_{\text{K}_\text{max}}(y_\oplus - 892)} \end{cases} \\ d_\text{K} &= (\frac{d_\oplus - d_{\text{K}_\text{offset}}(y_\oplus)}{d_{\oplus_\text{max}}(y_\oplus)} \times d_{\text{K}_\text{max}}(y_\text{K}) - 1) \bmod{d_{\text{K}_\text{max}}(y_\text{K})} + 1 \\ L &= \lfloor \frac{d_\text{K} - 1}{32} \rfloor + 1 \\ d_{\text{K}_L} &= \lfloor (d_\text{K} - 1) \bmod{32} \rfloor + 1 \end{aligned}