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Module:Keppel date/doc: Difference between revisions

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Tag: 2017 source edit
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;<code>day</code>
;<code>day</code>
:<math mode="display">\lfloor \text{yday} - \text{lythryd} * 32 \bmod{32} \rfloor</math>
:<math mode="display">\lfloor \text{yday} - \text{lythryd} * 32 \bmod{32} \rfloor</math>

<includeonly>[[Category:Modules: tesinormed]]</includeonly>
<includeonly>[[Category:Modules: tesinormed]]</includeonly>

Revision as of 22:01, March 4, 2025

Converts the current (or provided) date to a Keppel date. Used by Template:Keppel date.

Algorithm

Begin with the following inputs:

year
The current year in the Gregorian calendar.
yday
The current day of the year in the Gregorian calendar.

First, we define the following:

Earth leap year
\text{year} \bmod 400 = 0
\text{year} \bmod 4 = 0\text{ and not }\text{year} \bmod 100 = 0
Keppel leap year (schedule 1)
\text{year} \bmod 4 = 2
Keppel leap year (schedule 2)
\text{year} \bmod 239 = 65
ydayMaxEarth
If it is an Earth leap year, 366; else, 365.
ydayMax
Start with 389.
If it is a Keppel leap year (schedule 1), add one.
If it is a Keppel leap year (schedule 2), add one.
rolloverOffset
If it is an Earth leap year, 79; else, 78.

To calculate the result:

year
\text{year} - 892
If ydayPre is less than zero, subtract one.
ydayPre
\frac{\text{ydayMax} * (\text{yday} - \text{rolloverOffset})}{\text{ydayMaxEarth}}
yday
\text{ydayPre} \bmod{\text{ydayMaxEarth}}
If yday is between zero (inclusive) and one (exclusive), then yday is ydayMax.
lythryd
\lceil \frac{\text{yday}}{32} \rceil
day
\lfloor \text{yday} - \text{lythryd} * 32 \bmod{32} \rfloor